02-12-2018
Mathematics

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Please help ASAP! Algebra 2

Please help ASAP Algebra 2 class=

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jimrgrant1 jimrgrant1

02-12-2018

Answer:

0.216 = [tex]0.6^{3}[/tex]

Step-by-step explanation:

using the law of logarithms

• [tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]

given [tex]log_{0.6}[/tex] 0.216 = 3, then

0.216 = [tex]0.6^{3}[/tex]

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